The forces of `10^(6)` N each are applied on opposite directions on upper and lower faces of a cube of side 10 cm, shifting and lower faces of a cube of side 10 cm, shifting the upper face parallel to itself by 0.8 cm. If the side of the cube were 20 cm, Then the displacement of the cube will be

Options

A. 0.2 cm
B. 0.8 cm
C. 0.4 cm
D. 0.6 cm

Answer

C

Explanation

`eta=(Fh_(1))/(A_(1)x_(1))=(Fh_(2))/(A_(2)x_(2)) " " therefore A_(1)x_(1)=A_(2)x_(2)`