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Two person pull a rope towards themselves. Each person exerts a force of 100 N on the rope. Find the Young modulus of the material of the rope if it extends in length by 1 cm. Original length of the rope=2 m and the area of cross section =cm^2.

A

`10^(5)N//m^(2)`

B

`10^(6)N//m^(2)`

C

`10^(7)N//m^(2)`

D

`10^(8)N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`y=(FL)/(Al) =(100xx2)/(2xx10^(-4) xx 1xx10^(-2)) = 10^(8)N//m^(2)`.
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