The length of a metal wire is l when the tension is F and x l when the tension si y F. Then the natural length of the wire is

Options

A. `((x-y)l)/((x-1))`
B. `((y-x)l)/((y-1))`
C. `((x-y)l)/((x+1))`
D. `((y-x)l)/((y+1))`

Answer

B

Explanation

`L=(T_(2)l_(1)-T_(1)l_(2))/(T_(2)-T_(1))=(yFl-Fxl)/(yF-F)=((y-x)l)/(y-1)`.