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If young's modulus of steel is 2xx10^(11...

If young's modulus of steel is `2xx10^(11)N//m^(2)`, then the force required to increase the length of a wire of cross section `1 cm^(2)` by `1%` will be

A

`10^(5)N`

B

`2xx10^(5)N`

C

`10^(4)N`

D

`2xx10^(4)N`

Text Solution

Verified by Experts

The correct Answer is:
B
`F=(yAl)/(L)`
`F=2xx10^(11) xx 10^(-4) xx 10^(-2)`
`F=2xx10^(5)N`.
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