Two parallel forces of 4000 N are applied tangentially in opposite direction to the opposite faces of a metallic cube of side length 0.25 m. The shear modulus of the material is `80xx10^(9)` Pa. Then the displacement of the upper surface relative to the lower surface is

Options

A. `2xx10^(-5)m `
B. `2xx10^(-6)m `
C. `2xx10^(-7)m`
D. `2xx10^(-8)m `

Answer

C

Explanation

`x=(Fh)/(A eta) = (4000 xx 0.25)/(625xx10^(-4) xx 80xx10^(9)) = 2xx10^(-7)m.`