A body of volume `10^(-3)m^(3)` is compressed such that its volume decreases by `0.2xx10^(-6)m^(3)`. If its bulk modulus is `2xx10^(10)N//m^(2)`, then the pressure applied will be

Options

A. `2xx10^(6)N//m^(2)`
B. `3xx10^(6)N//m^(2)`
C. `4xx10^(6)N//m^(2)`
D. `6xx10^(6)N//m^(2)`

Answer

C

Explanation

`K=(vdp)/(dv) " " therefore dp=(kdv)/(v)`
`=(2xx10^(10) xx 0.2xx10^(-6))/(10^(-3)) = 0.4 xx 10^(-7)`
`=4xx10^(6)N//m^(2)`.