With the data of the above problem, the strain energy per unit volume stored in the wires is,

Options

A. `4xx10^(2)J//m^(3)`
B. `4 xx 10^(3)J//m^(3)`
C. `4 J//m^(3)`
D. `4xx10^(5)J//m^(3)`

Answer

D

Explanation

`u=(W)/(v) =(0.4)/(AL)=(0.4)/(10^(-6) xx1)`
`u=0.4xx10^(6)`
`=4xx10^(5) J//m^(3)`.