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A long elastic spring is stretched by 2 ...

A long elastic spring is stretched by `2 cm` and its potential energy is `U`. If the spring is stretched by `10 cm`, the `PE` will be

A

U/25

B

2U

C

5U

D

25U

Text Solution

Verified by Experts

The correct Answer is:
D
`(u_(2))/(u_(1)) =((1)/(2) kx_(2)^(2))/((1)/(2) kx_(1)^(2)) =((10)/(2))^(2)=25`
`u_(2) =25u.`
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