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A long elastic spring is stretched by 2 ...

A long elastic spring is stretched by 2 cm and its P.E. is 20 J. If the spring is stretched by by 10 cm, then its potential energy will be

A

100 J

B

250 J

C

200 J

D

500 J

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(1)=(1)/(2) K x_(1)^(2) and E_(2)=(1)/(2)K x_(2)^(2)`
`therefore E_(2)=(E_(1)x_(2)^(2))/(x_(1)^(2))`
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