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A copper rod 2m long is stretched by 1 m...

A copper rod 2m long is stretched by 1 mm, the energy stored per unit volume is, `(Y=1.2xx10^(11)N//m^(2))`

A

`10xx10^(3)J//m^(3)`

B

`20xx 10^(3)J//m^(3)`

C

`5xx10^(3)J//m^(3)`

D

`15xx10^(3)J//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`u=(1)/(2) " Stress" xx "Strain"=(1)/(2) Y("Strain")^(2)`
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