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A 2 kg weight is attached to the lower e...

A 2 kg weight is attached to the lower end of a spring which is hanging vertically producing in it an elongation of `4xx10^(-2)m`. Then potential energy of the stretched spring is

A

0.392 J

B

3.92 J

C

39.2 J

D

392 J

Text Solution

Verified by Experts

The correct Answer is:
A
`PE=(1)/(2)Fl`
`=(1)/(2) xx 2 xx 9.8 xx 4 xx 10^(-2) = 39.2 xx10^(-2)`
`=0.392J.`
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