A wire of area of cross section `1xx10^(-6)m^(2)` and length 2 m is stretched through `0.1 xx 10^(-3)m`. If the Young's modulus of a wire is `2xx10^(11)N//m^(2)`, then the work done to stretch the wire will be

Options

A. `0.05xx10^(-4)J`
B. `0.5xx10^(-4)J`
C. `5xx10^(-4)J`
D. `50xx10^(-4)J`

Answer

C

Explanation

`W=(1)/(2)Fl`
`=(1)/(2) xx (yAl^(2))/(L) =(1)/(2) xx (2xx10^(11) xx 10^(-6) xx 10^(-8))/(2)`
`=0.5 xx 10^(-3)`
`=5xx10^(-4)J`.