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A metal rod of length 2.5m and area of c...

A metal rod of length 2.5m and area of cross-section `2.5xx10^(-4)m^(2)` is elongated by `2.5xx10^(-3)`m by a force of 600N. Then energy stored in the rod is,

A

75 J

B

0.75 J

C

25 J

D

50 J

Text Solution

Verified by Experts

The correct Answer is:
B
`W=(1)/(2)Fl`
`=(1)/(2) xx 600 xx 2.5xx10^(-3)=0.75J`.
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