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Energy density of wire is 0.25 J//m^(3),...

Energy density of wire is `0.25 J//m^(3)`, when its extenstion is 0.2 cm. Find energy of wire, when elongation is 1 cm

A

`(25)/(4)J//m^(3)`

B

`(1)/(1000)J//m^(3)`

C

`(5)/(4)J//m^(3)`

D

`(25)/(2)J//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(u_(2))/(u_(1))=(l_(2)^(2))/(l_(1)^(2))=((1)/(0.2))^(2) =((10)/(2))^(2)=25`
`u_(2)=0.25 xx 25 =(25)/(4)`
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