The energy stored per unit volume in copper wire, which produces longitudinal strain of 0.1% is
`(Y = 1.1 xx 10^(11) N//m^(2))`

Options

A. `11xx10^(3) J//m^(3)`
B. `5.5xx10^(4)J//m^(3)`
C. `5.5 xx 10^(3)J//m^(3)`
D. `11xx10^(4)J//m^(3)`

Answer

B

Explanation

`(l)/(L)=(0.1)/(100)=0.001`
`u=(y)/(2)("strain")^(2)=(1.1)/(2)xx10^(11) xx 10^(-6)`
`=(1.1)/(2)xx 10^(5) =0.55 xx 10^(5) = 5.5 xx 10^(4)J//m^(3)`