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If M=mass of wire, rho=density of wire, ...

If M=mass of wire, `rho`=density of wire, R=radius of wire, r=change in radius, L=original length of wire and l=change in length, then poisson's ratio is given by

A

`(Mr rho)/(pi R^(3)l)`

B

`(Mr)/(pi R^(2)l rho)`

C

`(Mr)/(pi R^(3) rho l)`

D

`(Mr rho)/(pi r^(2)l)`

Text Solution

Verified by Experts

The correct Answer is:
C

`sigma=((r )/(R ))/((l)/(L))=(rL)/(Rr)`
`m=rho v=rho pi R^(2)L`
`therefore L=(M)/(rho pi R^(2))`
`sigma =(rM)/(rho pi R^(2)Rl)`
`sigma =(rM)/( rho pi R^(3)l)`
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