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Energy needed in breaking a drop of radi...

Energy needed in breaking a drop of radius `R` into `n` drops of radii `r` is given by

A

`4pi(r^(2)n-R^(2))T`

B

`(4/3 pi r^(2)n-4/3piR^(3))T`

C

` 4 pi (R^(2) - r^(2))nT`

D

` 4 pi (4n-R^(2))TP`

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The correct Answer is:
A
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