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A mercury drop of radius 1 cm is broken ...

A mercury drop of radius 1 cm is broken into `10^6` droplets of equal size. The work done is `(T=35xx10^-2(N)/(m)`)

A

`4.35 xx10^(-2)`J

B

`4.35 xx 10^(-3)`J

C

`4.35xx10^(-6)`J

D

`4.35 xx10^(-8)`J

Text Solution

Verified by Experts

The correct Answer is:
A

`dw = 4piR^(2)xxT (n^(1//3-1))`
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