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A soap bubble of radius 1//sqrtpi "cm" i...

A soap bubble of radius `1//sqrtpi "cm"` is expanded to radius `2//sqrtpi "cm".` Calculate the work done. Surface tension of soap solution `=30 "dyne"" "cm^(-1).`

A

120 erg

B

360 erg

C

720 erg

D

240 ergs

Text Solution

Verified by Experts

The correct Answer is:
C

Work done ` = T xx 2 xx dA`
` = T [ 4pi (2/(sqrt(pi)))^(2) - 4pi (1/(sqrt(pi)))^(2)]2`
` = 30 xx 12 xx 2 = 720 ` erg
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