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A ring of radius 0.75 cm is floating on ...

A ring of radius 0.75 cm is floating on the surface of water . If surface tension of water is 0.07 N/m the force required to lift the ring from the surface of water will be

A

`66xx 10^(-1)` N

B

` 66 xx 10^(-2)`N

C

`1.05 xx 10^(-3)` N

D

`66 xx 10^(-4)` N

Text Solution

Verified by Experts

The correct Answer is:
D
` F = T xx 2l `
` = 7 xx 10^(-2) xx 2xx 3.14 xx 0.75 xx 10^(-2)`
` = 66 xx 10^(4)` N .
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NIKITA PUBLICATION-SURFACE TENSION-Multiple Choice Questions (Surface energy and surface tension )
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  11. Eight droplets of water each of radius 0.5 mm when coalesce into singl...

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  13. If 64 raindrops combine into a single drop . The ratio of total surfa...

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  14. The surface tension of a liquid is 0.5 N/m . If a liquid film is form...

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  15. A soap film in formed on a frame of area 4xx10^(-3)m^(2). If the area ...

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  16. The surface energy of a soap film formed on a frame of area 2 xx 10^(...

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  17. The surface energy of a liquid drop is E. It is sprayed into 1000 equa...

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  18. The surface tension of soap solution is 10 xx 10^(-2) n/m . The am...

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  20. Work W is required to form a bubble of volume V from a given solution....

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