Eight droplets of water each of radius 0.5 mm when coalesce into single drop , then the change in surface energy will be ,

Options

A. `4pi T xx 10^(-5)` J
B. ` 4 pi T xx 10^(7)` J
C. ` 4pi T xx 10^(-6)` J
D. ` 4 pi T xx 10^(-8)` J

Answer

C

Explanation

`Delta E = E (n^(1//3)-1)= T 4piR^(2)(n^(1//3)-1)`