A soap film in formed on a frame of area...

A soap film in formed on a frame of area `4xx10^(-3)m^(2)`. If the area of the film in reduced to half, then the change in the potential energy of the film is (surface tension of soap solution`=40xx10^(-3)N//m)`

`160 `J

`160 xx 10^(-5)`J

`80 xx 10^(-6)`J

`1.6 xx 10^(-4)`J

Text Solution

Verified by Experts

The correct Answer is:

`W= S.T xx 2 `dA
` = 40 xx10^(-3) xx2 xx2xx10^(-3) = 6.4 xx10^(-4)` J

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