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If a vessel has a small hole at the bott...

If a vessel has a small hole at the bottom of radius 4 mm, then the rise of water in a vessel without leakage will be
(S.T = 72 dyne/cm , g = 1000 ` "cm/s"^(2) rho = 1 g //cm^(3)` )

A

` 0.36` cm

B

` 0.367` m

C

` 0.0367` cm

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`T = (hrhogr)/2 = hxx 1 xx(0.4xx100)/2` ,
` :. h = (72xx2)/(0.4xx1000)= 0.36` cm
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