The excess pressure inside one soap bubble is three times that inside a second bubble. The ratio of the volume of first bubble to that of the second

Options

A. `1:27`
B. `9:1`
C. `1:9`
D. `27:1`

Answer

A

Explanation

` (P_(1))/(P_(2)) = (r_(2))/(r_(1)) rArr (r_(2))/(r_(1))= 3 `
` V_(1) prop r_(1)^(3) and V_(2) prop r_(2)^(3)`
` (V_(1))/(V_(2)) = (r_(1)/(r_(2)))^(3)`