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Pressure inside two soap bubble are 1.02...

Pressure inside two soap bubble are 1.02 and 1.03 atm . Then ratio of their volumes is

A

`8 :27`

B

`27:8`

C

`(1.02)^(3) :(1.03)^(2)`

D

`(1.03)^(3):(1.02)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

` (V_(1))/(V_(2)) = ((P_(2))/(P_(1)))= ((0.03)/0.02 )^(3)= (3)^(2) : (2)^(3) = 27 : 8 `
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