The excess pressure inside a soap bubble of volume V is P . Then excess pressure inside a soap bubble of volume 2V is

Options

A. p
B. `2^(1//3)P`
C. `P//2^(1//3)`
D. P/1

Answer

C

Explanation

` (P_(2))/(P_(1)) = ((V_(1))/V_(2))^(1//3) :." " P_(2)= P/(2^(1//3))`