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If the surface tension of a soap water is 0.04 N/m Then excess pressure inside a 10 mm diameter soap bubble in `N//m^(2)` will be

A

4

B

16

C

8

D

32

Text Solution

Verified by Experts

The correct Answer is:
D
` P_(i)- P_(0)= (4T)/r `
` = (4xx 0.04)/(5 xx 10^(-3))= 16/5 xx 10 = 160/5 = 32 `
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