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Two soap bubbles are blown. In first soa...

Two soap bubbles are blown. In first soap bubble excess pressure is 4 times of the second soap bubble. The ratio of the radii of the first and second soap bubble is

A

`1:4`

B

`1:2`

C

`2:1`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
A

`P_(1)=4P_(2)`
` (P_(1))/(P_(2))= (r_(2))/(r_(1))`
` (4P_(2))/(P_(2)) = (r_(2))/(r_(1))`
` (r_(2))/(r_(1))=4/1 " " :. (r_(1))/(r_(2)) = 1/4 `
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