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Work done in forming a liquid drop of ra...

Work done in forming a liquid drop of radius R is `W_(1)` and that of radius 3R is `W_(2)`. The ratio of work done is

A

`1:3`

B

`1:4`

C

`1:2`

D

`1:9`

Text Solution

Verified by Experts

The correct Answer is:
D
` (W_(1))/(W_(2)) = ((R_(1))/(R_(2)))^(2) = (R/(3R))^(2)= 1 :9 `
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