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The relation between wave velocity and m...

The relation between wave velocity and maximum particle velocity is
(Where `V_(p)` = Particle velocity, V = Wave velocity)

A

`v_(p) = v`

B

`v_(p) = (lamda)/(2pi) v`

C

`v_(p) = (2piA)/(lamda)v`

D

`v = (lamda)/(2pi) v_(p)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(v_("max"))/(v) = (A omega)/(n lamda) = (A xx 2pi n)/(n lamda)`
`v_("max") = (2pi A)/(lamda) v`
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Knowledge Check

  • The relation between the particles velocity and wave velocity is -

    A
    `u = -v (dy)/(dx)`
    B
    `u = (V)/(((dy)/dx))`
    C
    u = V
    D
    `u = V + (dy)/(dx)`

  • The angle between wave velocity and particle velocity in a travelling wave be

    A
    zero
    B
    `(pi)/(2)`
    C
    `pi`
    D
    All of these

  • The phase difference between particle velocity and wave velocity is

    A
    zero
    B
    `(pi)/(4)`
    C
    `(pi)/(2)`
    D
    `(pi)/(6)`

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