Two waves are given by`y_(1) = a sin (omega t - kx)` and `y_(2) = a cos (omega t - kx)`. The phase difference between the two waves is

Options

A. `pi//2`
B. `pi//8`
C. `pi//8`
D. `2pi`

Answer

A

Explanation

`y_(1) = A sin (omegat - kx)`
`y_(2)= A sin(omega t-kx + (pi)/(2))`
`phi_(2) - phi_(1) = omega t - kx + (pi)/(2) - omega t + kx`
`= (pi)/(2)` rad