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The equation of a simple harmonic progre...

The equation of a simple harmonic progressive wave is given by
`y = 5 cos pi [200t - (x)/(150)]`
where x and y are in cm and 't' is in seocnd. The the velocity of the wave is

A

2 m/s

B

200 m/s

C

300 m/s

D

150 m/s

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AI Generated Solution

The correct Answer is:
To find the velocity of the wave given by the equation \( y = 5 \cos \left( \pi \left( 200t - \frac{x}{150} \right) \right) \), we can follow these steps: ### Step 1: Identify the wave equation format The standard form of a simple harmonic progressive wave is: \[ y = A \cos(\omega t - kx) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( k \) is the wave number. ### Step 2: Rewrite the given equation The given wave equation is: \[ y = 5 \cos \left( \pi \left( 200t - \frac{x}{150} \right) \right) \] We can expand this to: \[ y = 5 \cos \left( 200\pi t - \frac{\pi}{150} x \right) \] ### Step 3: Identify parameters From the equation, we can identify: - Amplitude \( A = 5 \) cm, - Angular frequency \( \omega = 200\pi \) rad/s, - Wave number \( k = \frac{\pi}{150} \) rad/cm. ### Step 4: Calculate frequency The relationship between angular frequency and frequency \( f \) is given by: \[ \omega = 2\pi f \] Substituting the value of \( \omega \): \[ 200\pi = 2\pi f \] Dividing both sides by \( 2\pi \): \[ f = \frac{200\pi}{2\pi} = 100 \text{ Hz} \] ### Step 5: Calculate wavelength The wave number \( k \) is related to the wavelength \( \lambda \) by: \[ k = \frac{2\pi}{\lambda} \] Substituting the value of \( k \): \[ \frac{\pi}{150} = \frac{2\pi}{\lambda} \] Cross-multiplying gives: \[ \lambda = 2 \times 150 = 300 \text{ cm} \] ### Step 6: Calculate wave velocity The velocity \( v \) of the wave can be calculated using the formula: \[ v = f \lambda \] Substituting the values of \( f \) and \( \lambda \): \[ v = 100 \text{ Hz} \times 300 \text{ cm} = 30000 \text{ cm/s} \] Converting to meters per second (since \( 1 \text{ m} = 100 \text{ cm} \)): \[ v = \frac{30000 \text{ cm/s}}{100} = 300 \text{ m/s} \] ### Final Answer The velocity of the wave is \( 300 \text{ m/s} \). ---

To find the velocity of the wave given by the equation \( y = 5 \cos \left( \pi \left( 200t - \frac{x}{150} \right) \right) \), we can follow these steps: ### Step 1: Identify the wave equation format The standard form of a simple harmonic progressive wave is: \[ y = A \cos(\omega t - kx) \] where: ...
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