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The phase of a particle at P(1) " is " 6...

The phase of a particle at `P_(1) " is " 60^(@)` and the phase of a particle at `P_(2) " is " 780^(@)`. If the distance between `P_(1) and P_(2)` is 1m, then the wavelength of the wave, will be

A

2m

B

0.5 m

C

1.5 m

D

0.25 m

Text Solution

Verified by Experts

The correct Answer is:
B
`delta = (2pix)/(lamda) , delta_(2) - delta_(1) = 780 - 60 = 720 = 4pi`
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