A small piece of cork in a ripple tank oscillates us and down as ripples pass it. If the ripples travelling at 0.3 m/s, have a wavelength of `1.5 pi` cm and the cork vibrates with an amplitude of 5mm, then the maximum velocity of the cork will be

Options

A. 20 cm/s
B. 0.02 cm/s
C. 20 m/s
D. 200 m/s

Answer

A

Explanation

`v_("max") = A omega`
`= 5 xx 10^(-1) xx 2 pi n = 10 pi (v)/(lamda) xx 10^(-1)`
`= (pi xx 0.3 xx 10^(2))/(1.5 pi) = 20 cm//s`