A sound wave of frequency 500 Hz covers a distance of 1000 m is 5 sec between the points X and Y. Then the number of waves between X and Y is

Options

A. 500
B. 2500
C. 1000
D. 5000

Answer

B

Explanation

`v = (d)/(t) = (1000)/(5) = 200 m//s`
`lamda = (v)/(n) = (200)/(500) = (2)/(5)`
`bar(lamda) = (1)/(lamda) = (5)/(2) xx 1000 = 2500`