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Two particles separated by a distance 16.5 mm in a progressive wave has a phase difference of `3pi//8` rad. If the number of waves passing across a point in the medium in 1s is 3750, then the velocity of wave will be

A

3300 m/s

B

330 cm/s

C

330 m/s

D

1650 m/s

Text Solution

Verified by Experts

The correct Answer is:
C

`x = 16.5 xx 10^(-3) m`
`delta = (2pi x)/(lamda) :. lamda = (2pi x)/(delta) = (2pi xx 16.5 xx 10^(-3))/((3pi)/(8))`
`lamda = (8 xx 2 xx 16.5 xx 10^(-3))/(3)`
`v = n lamda = (3750 xx 8 xx 2 xx 16.5 xx 10^(-3))/(3)`
`= 330 m//s`
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