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The displacement of a particle executing...

The displacement of a particle executing S.H.M. is given by `y = 10 sin [6t + (pi)/(3)]` where y is in metres and t is in seconds. Then the initial displacement and velocity of the particle is

A

`5sqrt3 m and 30 ms^(-1)`

B

`15 m and 5 sqrt3 ms^(-1)`

C

`15 sqrt3 and 30 ms^(-1)`

D

`20 sqrt3 and 30 ms^(-1)`

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The correct Answer is:
To find the initial displacement and velocity of the particle executing Simple Harmonic Motion (S.H.M.) given by the equation: \[ y = 10 \sin(6t + \frac{\pi}{3}) \] we will follow these steps: ### Step 1: Find the Initial Displacement The initial displacement occurs at \( t = 0 \). We can substitute \( t = 0 \) into the displacement equation. \[ y(0) = 10 \sin(6 \cdot 0 + \frac{\pi}{3}) \] This simplifies to: \[ y(0) = 10 \sin(\frac{\pi}{3}) \] ### Step 2: Calculate \( \sin(\frac{\pi}{3}) \) The value of \( \sin(\frac{\pi}{3}) \) is known to be \( \frac{\sqrt{3}}{2} \). \[ y(0) = 10 \cdot \frac{\sqrt{3}}{2} \] ### Step 3: Simplify the Initial Displacement Now, we can simplify this expression: \[ y(0) = 5\sqrt{3} \text{ meters} \] ### Step 4: Find the Initial Velocity The velocity in S.H.M. can be found by differentiating the displacement with respect to time \( t \). \[ v(t) = \frac{dy}{dt} = \frac{d}{dt} [10 \sin(6t + \frac{\pi}{3})] \] Using the chain rule, we have: \[ v(t) = 10 \cdot 6 \cos(6t + \frac{\pi}{3}) = 60 \cos(6t + \frac{\pi}{3}) \] ### Step 5: Calculate the Initial Velocity Now, we find the initial velocity at \( t = 0 \): \[ v(0) = 60 \cos(6 \cdot 0 + \frac{\pi}{3}) \] This simplifies to: \[ v(0) = 60 \cos(\frac{\pi}{3}) \] ### Step 6: Calculate \( \cos(\frac{\pi}{3}) \) The value of \( \cos(\frac{\pi}{3}) \) is known to be \( \frac{1}{2} \). \[ v(0) = 60 \cdot \frac{1}{2} \] ### Step 7: Simplify the Initial Velocity Now, we can simplify this expression: \[ v(0) = 30 \text{ meters per second} \] ### Final Results Thus, the initial displacement and velocity of the particle are: - Initial Displacement: \( 5\sqrt{3} \) meters - Initial Velocity: \( 30 \) meters per second ---

To find the initial displacement and velocity of the particle executing Simple Harmonic Motion (S.H.M.) given by the equation: \[ y = 10 \sin(6t + \frac{\pi}{3}) \] we will follow these steps: ### Step 1: Find the Initial Displacement The initial displacement occurs at \( t = 0 \). We can substitute \( t = 0 \) into the displacement equation. ...
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