If the maximum particle velocity is 3 times the wave velocity of a transverse wave of displacement amplitude 'a'. Then the phase difference between two particles separated by `(pia)/(2)` is

Options

A. `2pi//3`
B. `pi//3`
C. `3pi//2`
D. `3pi//4`

Answer

C

Explanation

`v_(p) = 3v`
`a omega = 3 n lamda`
`a xx 2pin = 3 n lamda`
`a xx (2pi)/(lamda) = 3`
`(2pi )/(lamda) = (3)/(a)`
`delta = ((2pi)/(lamda)) x`
`= (3)/(a) xx (pia)/(2) = (3)/(2) (pia)/(a) = (3pi)/(2)`