A man standing unsymmetrical position be...

A man standing unsymmetrical position between two mountains and fires a gun. He hears the first echo after 1.5 s and the second echo after 2.5 s. If the speed of sound is 340 m/s, then the nearest distance between the man and mountain will be

340 m

410 m

425 m

255 m

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The correct Answer is:

`x_(1) + (vt_(1))/(2)`

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