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Two sources A and B are sounding notes of frequency 680 Hz. A listener moves from A to B with a constant velocity u. If the speed of sound is 340 m/s, What must be the value of u so that he hears 10 beats per second?

A

2.0 m/s

B

2.5 m/s

C

3.0 m/s

D

3.5 m/s

Text Solution

Verified by Experts

The correct Answer is:
B
`n_(1) = n [(v + v_(0))/(v)] and n_(2) = n [(v- v_(0))/(v)]`
`n = n_(1) - n_(2) = (v)/(v) [v + v_(0) -v + v_(0)]`
`10 = (680)/(340) [2v_(0)]`
`v_(0) = (10)/(4) = 2.5 m//s`
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