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Two tuning forks A and B give 6 beats/s....

Two tuning forks A and B give 6 beats/s. The frequency of B is 432 Hz. When B is filed 4 beats/s are produced. The natural frequency of fork A is

A

438 Hz

B

426 Hz

C

483 Hz

D

462 Hz

Text Solution

Verified by Experts

The correct Answer is:
B

`n_(A) = n_(B) +- 6`
`= 432 +- 6 = 438 or 426 Hz`
When known fork is filled and sounded with a produces 4 b/s.
`n_(A) = n_(B) +- 4 = 432 +-4 = 436 or 426`
When fork of known frequency is filled its frequency decreases by difference of beat frequency (2Hz).
`:. n_(A) = 426 Hz`
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