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A set of 25 tuning forks is arranged in ...

A set of 25 tuning forks is arranged in order of decreasing frequency. Each fork gives 3 beats with succeeding one. The first fork is octave of the last. Calculate the frequency of the first and 16th fork.

A

144 Hz

B

99 Hz

C

95 Hz

D

85 Hz

Text Solution

Verified by Experts

The correct Answer is:
B

`N = (n_(f) - n_(L))/(x) + 1`
`25 -1 = (2n_(L) - n_(L))/(3)`
`24 xx 3 = n_(L)`
`72 = n_(L)`
`n_(f) = 2n_(2) = 2 xx 72 = 144`
`n_(1) - n_(2) = 3`
`n_(1) = n_(2) + 3`
`n_(1) = n_(3) + 2 xx 3`
`n_(1) = n_(16) + 15 xx 3`
`n_(16) = 144 - 45 = 99Hz`
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