If an observer moves towards a stationary source of sound with a velocity of one tenth the velocity of sound, then the apparent increase in frequency will be

Options

A. 0.01
B. 0.05
C. 0.1
D. `0.1`%

Answer

C

Explanation

`n' = n [(v + v_(0))/(v)]`
`:. n' = n [(v + (1//10) v)/(v)] = n[1.1]`
`(n' -n)/(n) = 0.1`
`:.` % increase of frequency = 10%