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A tuning fork of frequency 90 Hz is soun...

A tuning fork of frequency `90 Hz` is sounded and moved towards an observer with a speed equal to one - tenth the speed of sound. The note heard by the observer will have a frequency

A

100

B

90

C

450

D

900

Text Solution

Verified by Experts

The correct Answer is:
A
`n' = n [(v)/(v - v_(s))]`
`= 90 [(v)/(v - (v)/(10))] = 90 [(v)/((10v - v)/(10))]`
`= 90 [(10)/(9)] = 100 Hz`
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