The phase difference between two particles in a medium separated by a distance x is ` pi //6` .If the frequency of the oscillation is 50 Hz and the velocity of propagation of the wave is 100 m/s then x =

Options

A. 1/3 m
B. 1/4 m
C. 1/6 m
D. 1/12m

Answer

C

Explanation

`d = (2pi x)/(lamda)`
`x = (delta lamda)/(2pi) = ((pi)/(6) xx (v)/(n))/(2pi) = (1)/(12) xx (100)/(50) = (1)/(6) m`