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If the maximum particle velocity is 4 ti...

If the maximum particle velocity is 4 times of the wave velocity then relation between wavelength and amplitude is

A

`lamda = A//2pi`

B

`lamda = pi A//2`

C

`lamda = pi//2A`

D

`pi = lamda A//2`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_("pm") = 4v`
`A omega = 4n lamda`
`A 2pi n = 4 n lamda`
`lamda = (A pi)/(2)`
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