Home
Class 12
PHYSICS
Two identical waves each of frequency 10...

Two identical waves each of frequency 10Hz, are travelling in opposite directions in a medium with a speed of 20 cm/s . Then the distance between adjacent nodes is

A

1cm

B

1.2 cm

C

1.5 cm

D

2.0 cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the distance between adjacent nodes for two identical waves traveling in opposite directions, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - Frequency (f) = 10 Hz - Speed of waves (v) = 20 cm/s 2. **Use the Wave Equation**: The relationship between speed (v), frequency (f), and wavelength (λ) is given by the equation: \[ v = f \cdot \lambda \] 3. **Rearrange to Find Wavelength**: We can rearrange the equation to solve for the wavelength (λ): \[ \lambda = \frac{v}{f} \] 4. **Substitute the Values**: Now, substitute the given values into the equation: \[ \lambda = \frac{20 \, \text{cm/s}}{10 \, \text{Hz}} = 2 \, \text{cm} \] 5. **Determine the Distance Between Adjacent Nodes**: In a stationary wave, the distance between adjacent nodes is half the wavelength: \[ \text{Distance between nodes} = \frac{\lambda}{2} \] Substituting the value of λ: \[ \text{Distance between nodes} = \frac{2 \, \text{cm}}{2} = 1 \, \text{cm} \] ### Final Answer: The distance between adjacent nodes is **1 cm**. ---

To solve the problem of finding the distance between adjacent nodes for two identical waves traveling in opposite directions, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - Frequency (f) = 10 Hz - Speed of waves (v) = 20 cm/s ...
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTORS

    NIKITA PUBLICATION|Exercise MCQS|350 Videos
  • SURFACE TENSION

    NIKITA PUBLICATION|Exercise Multiple Choice Questions (Question Given in MHT-CET )|31 Videos

Similar Questions

Explore conceptually related problems

Two sound waves each of frequency 500Hz are travelling along the same line in opposite direction . If the speed of sound in air is 350 m/s. find the distance between the consecutive antinodes of the resulting stationary wave.

Two sinusoidal waves with identical wavelengths and amplitudes travel in opposite directions along a string with a speed of 15 cm/s. If the time interval between instants when the string is fiat is 0.20 s, what is the wavelength of the waves?

Two progressive sound waves each of frequency 170Hz and travelling in opposite directions in air superpose to produce stationary waves. The speed of sound in air is 340 m // s. What is the (i) separation between two successive nodes? (ii) separation between two successive antinodes? (iii) separation between a node and nearest antinode?

Two waves travelling in mutually opposite direction in a medium superimpose over each other, then which event is observed -

A stationary sound wave has a frequency of 165 Hz. If the speed of sound in air is 330 m/s , then the distance between a node and the adjacent antinode is

Stationary waves of frequency 300 Hz are formed in a medium in which the velocity of sound is 1200 metre / sec . The distance between a node and the neighbouring antinode is

Two waves, each having a frequency of 100 Hz and a wavelength of 2.0 cm, are travelling in the same direction on a string. What is the phase difference between the waves (a) if the second wave was produced 0.015 s later than the first one at the same place, (b) if the two waves were produced at the same instant but the first one was produced a distance 4.0 cm behind the second one ? (c) If each of the waves has an amplitude of 2.0 mm, what would be the amplitudes of the resultant waves in part (a) and (b) ?

NIKITA PUBLICATION-STATIONARY WAVES -MCQs
  1. The velocity of progressive wave which produces the stationary wave, ...

    Text Solution

    |

  2. In a stationary wave of frequency 200 Hz, the distance between a node ...

    Text Solution

    |

  3. Two identical waves each of frequency 10Hz, are travelling in opposite...

    Text Solution

    |

  4. The paritcle displacement (in cm) in a stationary wave is given by y(x...

    Text Solution

    |

  5. The frequency of the above stationary wave is

    Text Solution

    |

  6. Standing waves are produced by the superposition of two waves y(1)...

    Text Solution

    |

  7. The equation of the standing wave is y=0.02 cos((2pix)/(60))sin(150p...

    Text Solution

    |

  8. The maximum velocity of the particle in the above problem at a distanc...

    Text Solution

    |

  9. Two simple harmonic progressive waves is represented by y1=0.01 sin ...

    Text Solution

    |

  10. The amplitude of S.H.M. at antinodes of the problem No. 51 is

    Text Solution

    |

  11. The amplitude of S.H.M. at x=0.05 m is

    Text Solution

    |

  12. The distance between a node the next antinode is

    Text Solution

    |

  13. The distance between two adjacent antinodes is

    Text Solution

    |

  14. The equation of a stationary wave is given by y=6sin(pi)//(x)cos40pi...

    Text Solution

    |

  15. In the previous Q. The wavelength of the component progressive wave is

    Text Solution

    |

  16. In the Q.89 the frequency of the component progressive wave is

    Text Solution

    |

  17. The value of amplitude at an antinode , on an undamped one dimensiona...

    Text Solution

    |

  18. The value of amplitude at an antinode , on an undamped one dimensiona...

    Text Solution

    |

  19. The equation of a vibrating string is y=0.01cos4pixxsin200pit Wher...

    Text Solution

    |

  20. The velocity of the component wave is

    Text Solution

    |