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The paritcle displacement (in cm) in a s...

The paritcle displacement (in cm) in a stationary wave is given by `y(x,t)=2sin(0.1pix)cos(100pit)`. The distance between a node and the next antinode is

A

2.5 cm

B

5 cm

C

7.5 cm

D

10 cm

Text Solution

Verified by Experts

The correct Answer is:
B
`k=0.1pi therefore k=(2pi)/(lamda)=0.1pi`
`(2pi)/(lamda) = 0.1 pi therefore lamda=20cm`
The distance between node and next antinode is
`lamda/4=20/4=5cm`
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