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Standing waves are produced by the super...

Standing waves are produced by the superposition of
two waves
`y_(1)=0.05 sin (3 pit-2x) and y_(2) = 0.05 sin (3pit+2x)`
Where x and y are in metres and t is in second. What
is the amplitude of the particle at `x = 0.5` m ? (Given,
`cos 57. 3 ^(@) = 0. 54)`

A

2.7 cm

B

5.4 cm

C

9.98 cm

D

0.10 cm

Text Solution

Verified by Experts

The correct Answer is:
B
`R=2A cos ((2pix)/(lamda))`
`2xx0.05xxcos((2pixx0.5)/(pi))=0.1xxcos(1)^C`
`0.1cos(57.3)^@=0.1xx0.54=5.4cm`
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