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In the third of vibrations of the string...

In the third of vibrations of the string, the distance between extreme end nodes is 2m, then the position of the nodes from the ends will be

A

0.667m

B

0.333m

C

0.50m

D

0.25m

Text Solution

Verified by Experts

The correct Answer is:
A
`(3lamda)/(2) = 2 therefore lamda = 4/3`

The node next node is `=lamda/2 = 4/6 = 0.667 m`
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